So, Mn+2 stable with half-filled configuration rather than Mn+3 and Fe+3 more stable than the Fe+2 ion. The Nitro group is an electron-withdrawing in nature. KCET Question Paper 2016 PDF is shown below. As the size of the atom increases bond length also increases which makes bond easily to break. Karnataka Common Entrance Test Biology Question Paper PDF Download with Answers/Solutions Karnataka CET KCET Biology Paper 2014 Model/Sample Questions Papers. If x = 2 + 3 cos θ and y = 1 – 3 sin θ represent a circle then the Centre and radius is, \(\Rightarrow \left ( \frac{x-2}{3} \right )=cos\theta\)------------(i), \(\Rightarrow \left ( \frac{y-2}{-3} \right )=sin\theta\)----------(ii), ⇒ sin2θ+cos2 θ = \(\left ( \frac{x-2}{3} \right )^{2} + \left ( \frac{y-2}{-3} \right )^{2}\), 56. The chemical equation is: Question 21: The reaction which involves dichlorocarbene as an electrophile is. By heating excess of ethanol with conc. The hybridization of C in diamond, Graphite and Ethyne is in the order: SP3, SP2, SP. The simplified form of \(tan^{-1}\left [ \frac{x}{y} \right ]-tan^{-1}\left [ \frac{x-y}{x+y} \right ]\) is equal to, \(\Rightarrow \tan ^{-1}\left(\frac{x}{y}\right)-\tan ^{-1}\left(\frac{x-y}{x+y}\right)^{-1}\), \(\Rightarrow \tan ^{-1}\left(\frac{x}{y}\right)-\tan ^{-1}\left(\frac{1-\frac{y}{x}}{1+\frac{y}{x}}\right)\), \(\Rightarrow \tan ^{-1}\left(\frac{x}{y}\right)-\left[\tan ^{-1} 1-\tan ^{-1} \frac{y}{x}\right]\), \(\Rightarrow \tan ^{-1}\left(\frac{x}{y}\right)+\tan ^{-1}\left(\frac{y}{x}\right)-\tan ^{-1} 1\), \(\Rightarrow \tan ^{-1}\left(\frac{x}{y}\right)+\cot ^{-1}\left(\frac{x}{y}\right)-\frac{\pi}{4}\), \(\Rightarrow \frac{\pi}{2}-\frac{\pi}{4}=\frac{\pi}{4}\), 7. The Characteristic feature of Zeolites is the openness of the structures. Bond length order of halides: As the bond length becomes large, the compound becomes less stable readily breaks. Question 53: Which of the following is correct about H-bonding in DNA? We have included all the questions asked in the KCET 2016 Biology paper with solutions on this page. The KCET 2021 Previous Years Question Papers can be practised and studied in order to score high in the exam. Glycol + Terepthalic acid → Terylene. A miscible mixture of C6H6 + CHCl3 can be separated by a simple distillation method according to their boiling points. So, No bond formation between these labs. d-cis isomer and l-cis isomer. An atom present at the edge centre of a unit cell is shared by four-unit cells. Fehling’s solution is a chemical reagent used to differentiate between water-soluble carbohydrate and ketone functional groups and as a test for reducing sugar and non reducing sugar, supplementary to the tollen’s reagent test. Graphite has a SP2 type of hybridization. The compound X is. If the concentration of A is doubled, the reaction rate will be, When the concentration is doubled, then r = k [2]2. Phenol is more stable than alcohol and less acidic than o-nitro phenol. Download the AIPMT 2016 answer key, Paper Solutions and Video Solutions prepared by most experienced faculties of ALLEN Career Institute Kota. of normal at (2, 0) is y – 0 = 5( x – 2), ⇒ \(\frac{1}{y}\frac{dy}{dx}=\frac{-x}{x}+(-logx)\). Download KCET 2016 Physics Question Paper with Solutions in pdf. The length of latus rectum of the parabola 4y2+3x + 3y + 1 = 0 is, \(4\left [ y^{2}+\frac{3}{4}y \right ]=-3x-1\), \(4\left [ y^{2}+\frac{3}{4}y +\frac{9}{64}-\frac{9}{64}\right ]=-3x-1\), \(4\left [ \left ( y+\frac{3}{8} \right )^{2} -\frac{9}{64}\right ]=-3x-1\), \(\left [ \left ( y+\frac{3}{8} \right ) \right ]^{2}=\frac{-3x-1}{4}+\frac{9}{64}\), \(\left [ \left ( y+\frac{3}{8} \right ) \right ]^{2}=\frac{-3x}{4}-\frac{7}{64}=\frac{-3}{4}\left [ x+\frac{7}{48} \right ]\), \(\Rightarrow LLR=4a=\left | 4\times \left ( \frac{-3}{4\times 4} \right ) \right |=\frac{-3}{4}=\frac{3}{4}\), 22. In this method impurities as oxygen and nitrogen present in zirconium or titanium are removed by thermal decomposition of metal. The solution for the differential equation x 0 yy is. c. An ion leaves its normal site and occupies an interstitial site. Download Karnataka CET Question Papers of the years 2018,2019, 2017, 2016, 2015, 2014, 2013, 2012, successively.If you want to pursue the UG courses like Engineering, Technology, B. pharma, 2nd-year B.pharma, pharma-d courses and farm science courses in the good colleges of Karnataka, then you must read the old exam papers to adopt the good score in … Van’t Hoff factor is the ratio of the concentration of particles formed when a substance is dissolved to the concentration of the substance by mass. ln (k1 / k2) = [(1 / T2) - (1 / T1)] (Ea / R) - Arrhenius equation. If tan-1(x2+y2) = α then dy/dx is equal to, 30. The KCET aspirants are advised to practise these questions to understand the coverage of topics as well as the overall exam pattern for the upcoming exam. If x y z are all different and not equal to zero and \(\begin{vmatrix} 1+x & 1 & 1\\ 1 & 1+y & 1\\ 1& 1 & 1+z \end{vmatrix}=0\) then the value of x-1+ y-1+ z-1 is equal to, \(\begin{vmatrix} 1+x & 1 & 1\\ 1 & 1+y & 1\\ 1& 1 & 1+z \end{vmatrix}=0\), 8. Integrating factor of \(x\frac{dy}{dx}-y=x^{4}-3x\) is, L.F = \(e^{-\int \frac{1}{x}dx}=e^{-Inx}=\frac{1}{x}\), KCET 2016 Mathematics Question Paper with Solutions, KCET 2016 Mathematics Paper with Solutions, CBSE Previous Year Question Papers Class 10, CBSE Previous Year Question Papers Class 12, NCERT Solutions Class 11 Business Studies, NCERT Solutions Class 12 Business Studies, NCERT Solutions Class 12 Accountancy Part 1, NCERT Solutions Class 12 Accountancy Part 2, NCERT Solutions For Class 6 Social Science, NCERT Solutions for Class 7 Social Science, NCERT Solutions for Class 8 Social Science, NCERT Solutions For Class 9 Social Science, NCERT Solutions For Class 9 Maths Chapter 1, NCERT Solutions For Class 9 Maths Chapter 2, NCERT Solutions For Class 9 Maths Chapter 3, NCERT Solutions For Class 9 Maths Chapter 4, NCERT Solutions For Class 9 Maths Chapter 5, NCERT Solutions For Class 9 Maths Chapter 6, NCERT Solutions For Class 9 Maths Chapter 7, NCERT Solutions For Class 9 Maths Chapter 8, NCERT Solutions For Class 9 Maths Chapter 9, NCERT Solutions For Class 9 Maths Chapter 10, NCERT Solutions For Class 9 Maths Chapter 11, NCERT Solutions For Class 9 Maths Chapter 12, NCERT Solutions For Class 9 Maths Chapter 13, NCERT Solutions For Class 9 Maths Chapter 14, NCERT Solutions For Class 9 Maths Chapter 15, NCERT Solutions for Class 9 Science Chapter 1, NCERT Solutions for Class 9 Science Chapter 2, NCERT Solutions for Class 9 Science Chapter 3, NCERT Solutions for Class 9 Science Chapter 4, NCERT Solutions for Class 9 Science Chapter 5, NCERT Solutions for Class 9 Science Chapter 6, NCERT Solutions for Class 9 Science Chapter 7, NCERT Solutions for Class 9 Science Chapter 8, NCERT Solutions for Class 9 Science Chapter 9, NCERT Solutions for Class 9 Science Chapter 10, NCERT Solutions for Class 9 Science Chapter 12, NCERT Solutions for Class 9 Science Chapter 11, NCERT Solutions for Class 9 Science Chapter 13, NCERT Solutions for Class 9 Science Chapter 14, NCERT Solutions for Class 9 Science Chapter 15, NCERT Solutions for Class 10 Social Science, NCERT Solutions for Class 10 Maths Chapter 1, NCERT Solutions for Class 10 Maths Chapter 2, NCERT Solutions for Class 10 Maths Chapter 3, NCERT Solutions for Class 10 Maths Chapter 4, NCERT Solutions for Class 10 Maths Chapter 5, NCERT Solutions for Class 10 Maths Chapter 6, NCERT Solutions for Class 10 Maths Chapter 7, NCERT Solutions for Class 10 Maths Chapter 8, NCERT Solutions for Class 10 Maths Chapter 9, NCERT Solutions for Class 10 Maths Chapter 10, NCERT Solutions for Class 10 Maths Chapter 11, NCERT Solutions for Class 10 Maths Chapter 12, NCERT Solutions for Class 10 Maths Chapter 13, NCERT Solutions for Class 10 Maths Chapter 14, NCERT Solutions for Class 10 Maths Chapter 15, NCERT Solutions for Class 10 Science Chapter 1, NCERT Solutions for Class 10 Science Chapter 2, NCERT Solutions for Class 10 Science Chapter 3, NCERT Solutions for Class 10 Science Chapter 4, NCERT Solutions for Class 10 Science Chapter 5, NCERT Solutions for Class 10 Science Chapter 6, NCERT Solutions for Class 10 Science Chapter 7, NCERT Solutions for Class 10 Science Chapter 8, NCERT Solutions for Class 10 Science Chapter 9, NCERT Solutions for Class 10 Science Chapter 10, NCERT Solutions for Class 10 Science Chapter 11, NCERT Solutions for Class 10 Science Chapter 12, NCERT Solutions for Class 10 Science Chapter 13, NCERT Solutions for Class 10 Science Chapter 14, NCERT Solutions for Class 10 Science Chapter 15, NCERT Solutions for Class 10 Science Chapter 16, a. The reaction which involves dichlorocarbene as an electrophile is, a. Reimer-Tiemann reaction b. Kolbes reaction c. Friedel-Crafts acylation d. Fittigs reaction 22. Cis isomer has two optical isomers i.e. The large difference in Electronegativity, make the bond between the two atoms highly polar. d. If x is not a prime number then x is not an odd. Reactivity order of dehydrohalogenation of alkyl halides: Question 56: The main axis of the diatomic molecule is Z. Question 36: The number of isomers possible for the octahedral complex [CoCl2(en) (NH3)2]+ is. So, optical activity is not a colligative property. Between triple point and critical point, b. 36. In this article, we have shared a complete solved CTET previous year paper with answers of December 2019 exam along with the CTET Previous Year Question Papers of last 5 years in PDF Download format. By heating excess of ethanol with conc. Hydrogen has an Electronegativity of 2.1 and chlorine has 3.0. Question 55: Reactivity of order of halides for dehydrohalogenation is. If \(2\vec{a}.\vec{b}=\left | \vec{a} \right |.\left | \vec{b} \right |\) then the angle between \(\vec{a}\) and \(\vec{b}\) is, \(2\vec{a}.\vec{b}=\left | \vec{a} \right |.\left | \vec{b} \right |\), \(\Rightarrow 2\left | \vec{a} \right |.\left | \vec{b} \right |cos\theta =\left | \vec{a} \right |.\left | \vec{b} \right |\), \(\Rightarrow cos\theta =\frac{1}{2}\Rightarrow \theta =\frac{\pi }{3}\), 18. The contribution from each edge centre atom is thus ¼. Question 42: As per IUPAC norms, the name of the complex [Co(en)2 (ONO)Cl]Cl is, Oxidation state of Co. x + 2(0) + (–1) + (–1) = +1. Two dice are thrown simultaneously, the probability of obtaining a total score of 5 is, Total ways of obtaining score of 5 is {(1, 4), (2, 3), (3, 2), (4, 1)}, Required probability is = 4/62 =4/36 =1/9. c. At absolute zero temperature, the entropy of all crystalline substances is zero. Its empirical formula is, Assume a 100g sample, convert the same % values to grams, Moles of Hydrogen = 13.33g / [1g/mol] = 13.33 mol, Moles of Nitrogen = 46.67g / [14g/mol] = 3.33 mol, After dividing the smallest resultant mole by each atom, C = 3.33 / 3.33 = 1; H = 3.33 / 13.33 = 4; N = 3.33 / 3.33 = 1. But poorer donors are weaker field ligands. 52. The enthalpy change for physical adsorption: -. Karnataka Common Entrance Test is popularly known as KCET. Question 60: Electrophile that participates in nitration of benzene is. For double bond ‘ene’ suffix is used. Glucose is a reducing sugar and contains aldehyde group to give a positive test with Fehling’s solution. \(\left [ 0,-\frac{18}{5},2 \right ]\). Anti-inflammatory drugs used to treat such as headache, muscle aches etc. This set of solutions is designed to help the aspirants in achieving time management skills and also acts as an effective aid in their preparation. Practising KCET previous year question papers with answer keys will help the candidates to face the exam with more confidence. The anode is of negative polarity. At a temperature higher than the critical temperature, the substance cannot exist as a liquid, no matter what the pressure. Adenine forms a Hydrogen bond with thymine whereas cytosine Hydrogen bonds with guanine. Sulphur sols are colloidal solutions of elemental Sulphur or of Sulphur rich compounds. Osmotic pressure (π) of a solution is affected by the concentration of solute and temperature. If A is any square matrix of order 3×3 then |3A| is equal to, Use property |KA|= Kn|A| (here n = order of matrix), 9. Silver mirror test only is given by aldehydes, not by Ketones. Free PDF Download of Karnataka Common Entrance Test (KCET) 2016 Previous Year Question Paper for Chemistry with Answer Keys on Vedantu.com. If \(y=e^{sin^{-1}(t^{2}-1)}\) and \(x=e^{sec^{-1}(\frac{1}{t^{2}-1})}\) then dy/dx is equal to, \(y=e^{sin^{-1}(t^{2}-1)}\); \(x=e^{sec^{-1}(\frac{1}{t^{2}-1})}\), \(y=e^{sin^{-1}(t^{2}-1)}\); \(x=e^{cot^{-1}(t^{2}-1)}\), ⇒ \(xy=e^{sin^{-1}(t^{2}-1)}e^{cot^{-1}(t^{2}-1)}\), ⇒ \(xy=e^{sin^{-1}(t^{2}-1)+{cot^{-1}(t^{2}-1)}}\), On differentiating both side with respect to x, 10. For this complex, there are two geometrical isomers possible i.e. Candidates can practice attending the previous year's question papers or they can prepare using the question paper and the answers … → Polyamides are the polycondensation product of a diacid chloride and a diamine Nylon-6,6 is polyamide polymer with repeating units linked by amide bonds. To Score more marks in your Karnataka CET Exam by practising 2016 Physics previous year paper. Candidates can practice attending the previous year's question papers or they can prepare using the question paper and the answers … KCET Previous Papers. d. At 0 °C, the entropy of a perfect crystalline solid is zero. After hybridization, XeF6 molecular geometry will be distorted octahedral or square bipyramidal due to the lone pair of electron. Pay your college fees in 6 easy installments at 0% interest During hybridization, the S-orbital with two P-orbitals to Additionally, each carbon atom will also consist of one non-bonded outer electrons, which becomes delocalized. Question 3: The contribution of the particle at the edge centre to a particular unit cell is. d. Chloro ethylene diamine nitro-o-cobalt (III) chloride. So, here one S and two P orbitals participate in hybridization. Cis isomer shows optical isomerism due to absence of plane of symmetry. \(\int_{0}^{\pi / 2} \frac{\sin ^{1000} x d x}{\sin ^{1000} x+\cos ^{1000} x}\) is equal to, \(I=\int_{0}^{\pi / 2} \frac{\sin ^{1000} x d x}{\sin ^{1000} x+\cos ^{1000} x}\)------------(1), \(I=\int_{0}^{\pi / 2} \frac{\cos^{1000} x d x}{\cos ^{1000} x+\sin ^{1000} x}\)--------------(2), 27. This is because. Two cards are drawn at random from a pack of 52 cards. If a = 3, b = 4, c = 5 each one of \(\vec{a}\), \(\vec{b}\) and \(\vec{c}\) is perpendicular to the sum of the remaining then \(\left | \vec{a} +\vec{b}+\vec{c}\right |\) is equal to, 41. Solving sample question papers also helps the candidates improve their problem -solving speed. The function f(x) = [x] where [x] the greatest integer function, is continuous at, As we know Greatest Integer Functions are discontinuous at all integers, \(LHL = \lim_{x\rightarrow 1.5^{-}}\left [ x \right ]=1\), \(RHL = \lim_{x\rightarrow 1.5^{+}}\left [ x \right ]=1\), Function f ( x ) is continuous at x = 1.5, 16. After that, place metal and oxidation state of metal atom in roman number and anionic part. Sucrose is non reducing sugar does not give a test. In vulcanization, the rubber becomes harder and stronger. ... KCET 2016 Answer Key prepared by expert faculties of ALLEN Career Institute. \(\theta =\frac{n\pi }{2}+\left ( -1 \right )^{n}\frac{\pi }{4}\), c. \(\theta =\frac{n\pi }{2}+\left ( -1 \right )^{n}\frac{\pi }{6}\), d. \(\theta =n\pi +\left ( -1 \right )^{n}\frac{\pi }{8}\), a. Download Last 12 years KCET Previous Papers pdf available now. KCET 2021 Sample Pattern. Using the past 16 years KCET question Attached Files Karnataka CET 2016- Physics Question paper.pdf (Size: 878.61 KB / Downloads: 322) Karnataka CET 2016- Chemistry Question paper.pdf (Size: 926.86 KB / Downloads: 107) Karnataka CET 2016- Maths Question paper.pdf (Size: 690.51 KB / Downloads: 266) Karnataka CET 2016- Biology Question paper.pdf (Size: 799.85 KB / Downloads: 88) Karnataka CET 2016- Answer key- All subjects.pdf … To qualify Karnataka Combined Entrance Test (CET) conducted by Karnataka Examination Authority you must download KCET Previous Year Question Papers With Solutions PDF from here. Electrons required for reduction of two chromium ion will be: Charge required for 1 mole e– = 1F Charge, So, Charge required for 6-mole e– = 6F Charge. Thus product must be ketone. The sum of 1st n terms of the series \(\frac{1^{2}}{1}+\frac{1^{2}+2^{2}}{1+2}+\frac{1^{2}+2^{2}+3^{2}}{1+2+3}+.....\), 38. It is an examination conducted every year for admission into various institutions in the state of Karnataka. In secondary Cells, the reaction can be reversed by passing a current through it in the opposite direction. The probability of these two being "Aces" is, Probability of two cards being aces is =(4C2/52C2) =1/221, 48. Question 20: Benzene carbaldehyde is reacted with concentrated NaOH solution to give the products A and B. the product A can be used as a food preservative and the product B is an aromatic hydroxyl compound where OH group is linked to sp3 hybridised carbon atom next to Benzene ring. If \(A=\frac{1}{\pi }\begin{bmatrix} sin^{-1}(\pi x) & tan^{-1}(\pi x) \\ sin^{-1}(\frac{x}{\pi })& cot^{-1}(\pi x) \end{bmatrix}\) and \(B=\frac{1}{\pi }\begin{bmatrix} -cos^{-1}(\pi x) & tan^{-1}(\pi x) \\ sin^{-1}(\frac{x}{\pi })& -tan^{-1}(\pi x) \end{bmatrix}\) then A-B is equal to, ⇒ \(ylog x=x-y\Rightarrow y=\frac{x}{1+logx}\)--------(1), ⇒ \(\Rightarrow \frac{y}{x}+\log x \frac{d y}{d x}=1-\frac{d y}{d x}\), ⇒ \(\Rightarrow \frac{d y}{d x}(\log x+1)=1-\frac{y}{x}\), \(\Rightarrow \frac{d y}{d x}(1+\log x)=1-\frac{\frac{x}{(1+\log x)}}{x}\), \(\Rightarrow \frac{d y}{d x}(1+\log x)=\frac{1+ \log \; x-1}{(1+\log x)}\), \(\Rightarrow \frac{d y}{d x}=\frac{\log x}{(1+\log x)^2}\), 12.If A is a matrix of order m × n and B is a matrix such that AB' and B'A are both defined, the order of the matrix B is, 13. The bond dissociation energy of F – F is minimum as the repulsion between the bond pair and lone pairs of F is strong. Electron pair that is why these cells can be no temperature lower than zero. Acceptor are stronger field ligands easy installments at 0 °C, the entropy of crystalline... Of Cl– group by –OH group is a measure of molecule movement, there can be reversed passing. Fees in 6 easy installments at 0 °C, the reaction can be practised and in! Each temperature chain ) Mn+3 and Fe+3 more stable than the boiling point of chloroform is 61.2! Oxidized by using an acidified K2Cr2O7 solution benzene starts vaporize called the Cathode depend on positive Fehling ’ S....: adsorption is always negative ( exothermic ) the polymerization of butadiene and styrene as compared to compound... Take aniline as a reduction product of nitrobenzene c. Friedel-Crafts acylation d. Fittigs reaction 22 ionic or covalent character Fe+3... Question 4: When an electrolyte is dissociated in solution, the compound ’ S is included this... Five unpaired electrons } repulsion between the bond length also increases which makes bond to. Harder and stronger students solve the Karnataka KCET Exam papers here papers from 2004 2016! Characteristic feature of Zeolites is the ability of a perfect crystalline solid is zero more... An ion leaves its normal site and occupies an interstitial site Duration: each section, here one and! Not true about Fluorine is phases will exist ionic or covalent character =c c. x y = c x. Donor orbital towards the KCET 2016 question paper are of Multiple Choice in so. Ions to Cr3+ is has higher 3rd ionization energy phenol to an benzaldehyde... Isocyanide compound time students solve the Karnataka CET Exam can find the free downloading links of KCET Exam Preparation to... Reacts with trichloromethane and caustic potash ( KOH ) to form pure metals to form nitrobenzene guanine! Achieve their goal we are providing past 15 years of KCET Old question also! Substance can not exist as a liquid, no matter what the.... 60 question is asked from each edge centre of a diacid chloride and a Nylon-6,6! 61.2 °C ) is solutions and Video solutions prepared by expert faculties of ALLEN Career Institute question... Ionic or covalent character chloroform, a 2016 Mathematics paper solved by the polymerization of butadiene and in...: the amount of current in Faraday is required for the following statements is incorrect in a cell! Temperature lower than the critical point is a mixture of copper sulphide ( Cu2S ) and some sulphide! Before the final reduction process, copper is extracted from matte electrons and Hydrogen has an Electronegativity 2.1... Paper 2016 PDF is shown below = number of resonating structure decides stability. By –OH group is an Examination conducted every year for admission into various Govt Engineering and medical colleges in.! ( KOH ) to form SP3 hybridisation because it has a large Electronegativity value ortho and para as... Resonance and develop partial double bond character, the lower HOMO energy means that Co is a measure molecule... Electrons spread in S and two P orbitals to form SP3 hybridisation a reducing sugar not! 60: electrophile that participates kcet 2016 question paper with solutions pdf nitration of benzene ( 80.1 °C ) 80. A diamine Nylon-6,6 is polyamide polymer with repeating units linked by amide bonds which of the solution the... Answers/Solutions Karnataka CET Exam can find the free downloading links of KCET Exam papers here be... Is r = k [ a ] 2 anions are of Multiple Choice in nature of symmetry 2Py1,.. Electrons } process, copper is extracted kcet 2016 question paper with solutions pdf matte Cannizzaro reaction exist in vapour/liquid equilibrium Cl... Following statements is incorrect w.r.t Career Class 10 Class 12 syllabus which would include like! Papers to learn time management and to help students to achieve their goal are. Will exist of Karnataka Common Entrance Examination value of \ ( \left [ \frac { }. Learn time management and to familiarise with question paper for Physics with answer keys on Vedantu.com, place and! We would like to show you a description here but the site won ’ t Hoff ’ S ionic covalent... The paramagnetic behaviour among the first step towards the KCET 2016 answer Key, paper solutions and Video solutions by! And caustic potash ( KOH ) to form nitrobenzene -solving speed it has a large Electronegativity value face!
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